Solve the Problem $\theta$ Of the Sun in the Sky at Any Latitude

question 114

Multiple Choice

Solve the problem.
-The angle of elevation $\theta$ of the sun in the sky at any latitude $L$ is calculated with the formula $\sin \theta = \cos \mathrm { D } \cos \mathrm { L } \cos \omega + \sin \mathrm { D } \sin \mathrm { L }$ . $\omega$ is the number of radians that the Earth has rotated through since noon when $\omega = 0$ . D is the declination of the sun. Westville has latitude $L = 36.5 ^ { \circ }$ . Find the angle of elevation $\theta$ in degrees of the sun at 3 PM on February 29, 2012, where at that time $\mathrm { D } \approx - 0.1425$ and $\omega \approx 0.7854$ .

• A) \(9.8 ^ { \circ }\)
• B) \(0.5 ^ { \circ }\)
• C) \(28.6 ^ { \circ }\)
• D) \(27.4 ^ { \circ }\)

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