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A Loop of Diameter D = 12 Cm, Carrying a Current

question 9

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A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field   = (0.2 T)    + (0.4 T)    . The normal to the loop is parallel to the unit vector   . What is the potential energy of the loop? A) -4.5 × 10<sup>-4</sup> J B) +9.0 × 10<sup>-4</sup> J C) -9.0 × 10<sup>-4</sup> J D) -2.3 × 10<sup>-4</sup> J E) +4.5 × 10<sup>-4</sup> J = (0.2 T) A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field   = (0.2 T)    + (0.4 T)    . The normal to the loop is parallel to the unit vector   . What is the potential energy of the loop? A) -4.5 × 10<sup>-4</sup> J B) +9.0 × 10<sup>-4</sup> J C) -9.0 × 10<sup>-4</sup> J D) -2.3 × 10<sup>-4</sup> J E) +4.5 × 10<sup>-4</sup> J + (0.4 T) A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field   = (0.2 T)    + (0.4 T)    . The normal to the loop is parallel to the unit vector   . What is the potential energy of the loop? A) -4.5 × 10<sup>-4</sup> J B) +9.0 × 10<sup>-4</sup> J C) -9.0 × 10<sup>-4</sup> J D) -2.3 × 10<sup>-4</sup> J E) +4.5 × 10<sup>-4</sup> J . The normal to the loop is parallel to the unit vector A loop of diameter d = 12 cm, carrying a current I = 0.4 A is placed inside a magnetic field   = (0.2 T)    + (0.4 T)    . The normal to the loop is parallel to the unit vector   . What is the potential energy of the loop? A) -4.5 × 10<sup>-4</sup> J B) +9.0 × 10<sup>-4</sup> J C) -9.0 × 10<sup>-4</sup> J D) -2.3 × 10<sup>-4</sup> J E) +4.5 × 10<sup>-4</sup> J . What is the potential energy of the loop?


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