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The Position Vector of an Object of Mass 0

question 14

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The position vector of an object of mass 0.50 kg subject to a constant force is given by The position vector of an object of mass 0.50 kg subject to a constant force is given by   = (at<sup>2</sup>+bt)    + (ct<sup>2</sup>+dt)    + (et<sup>2</sup>+ft)    , where a = 2.0 m/s<sup>2</sup>, b = 3.0 m/s, c = 2.5 m/s<sup>2</sup>, d = -2.0 m/s, e = 1.0 m/s<sup>2</sup>, and f = 4.0 m/s. What is the angular momentum of the object about the origin at t = 2.0 s? A) (24   - 122   - 89   )  kg∙m<sup>2</sup>/s B) (-24   + 10   + 23   )  kg∙m<sup>2</sup>/s C) (25   - 14   + 20   )  kg∙m<sup>2</sup>/s D) (25   + 14   + 20   )  kg∙m<sup>2</sup>/s E) (24   + 122   + 23   )  kg∙m<sup>2</sup>/s = (at2+bt) The position vector of an object of mass 0.50 kg subject to a constant force is given by   = (at<sup>2</sup>+bt)    + (ct<sup>2</sup>+dt)    + (et<sup>2</sup>+ft)    , where a = 2.0 m/s<sup>2</sup>, b = 3.0 m/s, c = 2.5 m/s<sup>2</sup>, d = -2.0 m/s, e = 1.0 m/s<sup>2</sup>, and f = 4.0 m/s. What is the angular momentum of the object about the origin at t = 2.0 s? A) (24   - 122   - 89   )  kg∙m<sup>2</sup>/s B) (-24   + 10   + 23   )  kg∙m<sup>2</sup>/s C) (25   - 14   + 20   )  kg∙m<sup>2</sup>/s D) (25   + 14   + 20   )  kg∙m<sup>2</sup>/s E) (24   + 122   + 23   )  kg∙m<sup>2</sup>/s + (ct2+dt) The position vector of an object of mass 0.50 kg subject to a constant force is given by   = (at<sup>2</sup>+bt)    + (ct<sup>2</sup>+dt)    + (et<sup>2</sup>+ft)    , where a = 2.0 m/s<sup>2</sup>, b = 3.0 m/s, c = 2.5 m/s<sup>2</sup>, d = -2.0 m/s, e = 1.0 m/s<sup>2</sup>, and f = 4.0 m/s. What is the angular momentum of the object about the origin at t = 2.0 s? A) (24   - 122   - 89   )  kg∙m<sup>2</sup>/s B) (-24   + 10   + 23   )  kg∙m<sup>2</sup>/s C) (25   - 14   + 20   )  kg∙m<sup>2</sup>/s D) (25   + 14   + 20   )  kg∙m<sup>2</sup>/s E) (24   + 122   + 23   )  kg∙m<sup>2</sup>/s + (et2+ft) The position vector of an object of mass 0.50 kg subject to a constant force is given by   = (at<sup>2</sup>+bt)    + (ct<sup>2</sup>+dt)    + (et<sup>2</sup>+ft)    , where a = 2.0 m/s<sup>2</sup>, b = 3.0 m/s, c = 2.5 m/s<sup>2</sup>, d = -2.0 m/s, e = 1.0 m/s<sup>2</sup>, and f = 4.0 m/s. What is the angular momentum of the object about the origin at t = 2.0 s? A) (24   - 122   - 89   )  kg∙m<sup>2</sup>/s B) (-24   + 10   + 23   )  kg∙m<sup>2</sup>/s C) (25   - 14   + 20   )  kg∙m<sup>2</sup>/s D) (25   + 14   + 20   )  kg∙m<sup>2</sup>/s E) (24   + 122   + 23   )  kg∙m<sup>2</sup>/s , where a = 2.0 m/s2, b = 3.0 m/s, c = 2.5 m/s2, d = -2.0 m/s, e = 1.0 m/s2, and f = 4.0 m/s. What is the angular momentum of the object about the origin at t = 2.0 s?

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Refers to the distinct division or distance between entities or areas, often implying a lack of direct interaction or connection.

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A pricing strategy where a company charges different prices for the same product or service to different customers, based on the willingness to pay.

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The phenomenon where goods or services are sold at varying prices due to factors such as location, demand, or quality.

Pure Monopolist

A single supplier dominates the entire market for a particular good or service, without any competition.

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