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Solve the problem.
-One number is 4 less than a second number. Twice the second number is 17 more than 3 times the first. Find the two numbers.
Q15: <span class="ql-formula" data-value="f ( x ) =
Q16: <span class="ql-formula" data-value="- 4 x \geq 24"><span
Q25: <span class="ql-formula" data-value="\sqrt [ 4 ] {
Q25: Find <span class="ql-formula" data-value="f (
Q63: A number decreased by 78<br>A) 78x<br>B) x
Q67: <span class="ql-formula" data-value="4 y = - 12"><span
Q81: Find <span class="ql-formula" data-value="f (
Q90: <span class="ql-formula" data-value="\frac { \frac { 16
Q97: {(6,-8), (1,3), (-9,-9), (-2,2), (5,-6)}<br>A) domain =
Q164: <span class="ql-formula" data-value="16 - \sqrt { 2