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Solve the Problem P(A)=0.22P ( A ) = 0.22 And P(B)=0.36P ( B ) = 0.36

question 144

Multiple Choice

Solve the problem.
-Suppose that P(A) =0.22P ( A ) = 0.22 and P(B) =0.36P ( B ) = 0.36 , find P(AB) P ( A \cup B ) if AA and BB are mutually exclusive.


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