Find the Real Solutions, If Any, of the Equation $\left\{\frac{-6-\sqrt{39}}{3}, \frac{-6+\sqrt{39}}{3}\right\}$

question 183

Multiple Choice

Find the real solutions, if any, of the equation. Use the quadratic formula.
-3x² + 12x + 1 = 0

• A)\( \left\{\frac{-6-\sqrt{39}}{3}, \frac{-6+\sqrt{39}}{3}\right\} \)
• B)\( \left\{\frac{-6-\sqrt{33}}{6}, \frac{-6+\sqrt{33}}{6}\right\} \)
• C)\( \left\{\frac{-6-\sqrt{33}}{3}, \frac{-6+\sqrt{33}}{3}\right\} \)
• D)\( \left\{\frac{-12-\sqrt{33}}{3}, \frac{-12+\sqrt{33}}{3}\right\} \)

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