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Solve the Three-Part Linear Inequality 03x+43<40 \leq \frac { 3 x + 4 } { 3 } < 4

question 192

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Solve the three-part linear inequality. Graph the solution set on a number line, and express the solution using interval notation.
- 03x+43<40 \leq \frac { 3 x + 4 } { 3 } < 4  Solve the three-part linear inequality. Graph the solution set on a number line, and express the solution using interval notation. - 0 \leq \frac { 3 x + 4 } { 3 } < 4    A)   \left[ - \frac { 4 } { 3 } , \frac { 8 } { 3 } \right]    B)   \left( - \frac { 4 } { 3 } , \frac { 8 } { 3 } \right)     C)   \left[ - \frac { 4 } { 3 } , \frac { 8 } { 3 } \right]    D)   \left[ - \frac { 4 } { 3 } , \frac { 8 } { 3 } \right]


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