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A Projectile Is Launched from Ground Level at an Angle θ\theta

question 30

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A projectile is launched from ground level at an angle of θ\theta with the horizontal. The initial velocity is v0v _ { 0 } feet per second and the path of the projectile is modeled by the parametric equations x=(v0cosθ) t and y=(v0sinθ) t16t2x = \left( v _ { 0 } \cos \theta \right) t \text { and } y = \left( v _ { 0 } \sin \theta \right) t - 16 t ^ { 2 } \text {. }
Use a graphing utility to graph the paths of a projectile launched from ground level with the values given for θ\theta and v0v _ { 0 } . Use the graph to approximate the maximum height and range of the projectile to the nearest foot.
θ=55,v0=56 feet per second \theta = 55 ^ { \circ } , \quad v _ { 0 } = 56 \text { feet per second }


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