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Solve the Following System of Quadratic Equations Algebraically by the Method

question 24

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Solve the following system of quadratic equations algebraically by the method of substitution.
{4x23y2+48=04x2y=0\left\{ \begin{array} { l } - 4 x ^ { 2 } - 3 y ^ { 2 } + 48 = 0 \\- 4 x - 2 y = 0\end{array} \right.


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