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A Projectile Is Launched from Ground Level at an Angle θ\theta

question 18

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A projectile is launched from ground level at an angle of θ\theta with the horizontal. The initial velocity is v0v _ { 0 } feet per second and the path of the projectile is modeled by the parametric equations x=(v0cosθ) tx = \left( v _ { 0 } \cos \theta \right) t and y=(v0sinθ) t16t2.y = \left( v _ { 0 } \sin \theta \right) t - 16 t ^ { 2 } .
Use a graphing utility to graph the paths of a projectile launched from ground level with the values given for θ\theta and v0v _ { 0 } . Use the graph to approximate the maximum height and range of the projectile to the nearest foot.
θ=50,v0=104 feet per second \theta = 50 ^ { \circ } , \quad v _ { 0 } = 104 \text { feet per second }

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