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Solve the Following System of Quadratic Equations Algebraically by the Method

question 72

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Solve the following system of quadratic equations algebraically by the method of substitution.
{8x26y2+80=08x+4y=0\left\{ \begin{array} { l } 8 x ^ { 2 } - 6 y ^ { 2 } + 80 = 0 \\8 x + 4 y = 0\end{array} \right.


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