Find $$\lim _ { x \rightarrow 6 } \frac { \sqrt { x + 7 } } { x - 2 }$$

question 40

Multiple Choice

Find
$$\lim _ { x \rightarrow 6 } \frac { \sqrt { x + 7 } } { x - 2 }$$
by direct substitution.

• A) \(\frac { \sqrt { 6 } } { 4 }\)
• B) \(\frac { \sqrt { 13 } } { 2 }\)
• C) \(\frac { \sqrt { 13 } } { 4 }\)
• D) \(\frac { 1 } { 4 }\)
• E) \(\sqrt { 13 }\)

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