Use Mathematical Induction to Prove That$1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all } n \geq 1$

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The Answer of Use Mathematical Induction to Prove That$1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all } n \geq 1$

Use Mathematical Induction to Prove That $1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all } n \geq 1$

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Use Mathematical Induction to Prove That 1+4+7+10+⋯+(3n−2)=n(3n−1)2 for all n≥11 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all } n \geq 11+4+7+10+⋯+(3n−2)=2n(3n−1)​ for all n≥1

Definitions:

Use Mathematical Induction to Prove That $1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all } n \geq 1$