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Show That the Boolean Function F given by F(x,y,z)=x(z+yz)+y(xzx) simplifies to xz+xˉy, by using F \text { given by } F ( x , y , z ) = x ( z + y z ) + y ( \overline { x z } x ) \text { simplifies to } x z + \bar { x } y \text {, by using }

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Show that the Boolean function F given by F(x,y,z)=x(z+yz)+y(xzx) simplifies to xz+xˉy, by using F \text { given by } F ( x , y , z ) = x ( z + y z ) + y ( \overline { x z } x ) \text { simplifies to } x z + \bar { x } y \text {, by using } only the definition of a Boolean algebra.

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