Solve the Differential Equation $$x y ^ { \prime } + 4 y = \frac { \cos x } { x ^ { 3 } } , x > 0$$

question 28

Multiple Choice

Solve the differential equation.
- $$x y ^ { \prime } + 4 y = \frac { \cos x } { x ^ { 3 } } , x > 0$$

• A) \(y = \frac { \cos x + C } { x ^ { 3 } } , x > 0\)
• B) \(y = \frac { \cos x + C } { x ^ { 4 } } , x > 0\)
• C) \(y = \frac { \sin x + C } { x ^ { 3 } } , x > 0\)
• D) \(y = \frac { \sin x + C } { x ^ { 4 } } , x > 0\)

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