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Solve the Problem Ldidt+Ri=0\mathrm { L } \frac { \mathrm { di } } { \mathrm { dt } } + \mathrm { Ri } = 0

question 70

Multiple Choice

Solve the problem.
-If the switch is thrown open after the current in an RL circuit has built up to its steady-state value, the decaying current obeys the equation Ldidt+Ri=0\mathrm { L } \frac { \mathrm { di } } { \mathrm { dt } } + \mathrm { Ri } = 0 . How long after the switch is thrown open will it take the current to fall to 35%35 \% of its original value?


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