Solve the Initial Value Problem for X as a Function $$\left( t ^ { 2 } - 5 t + 6 \right) \frac { d x } { d t } = 1 \quad ( t > 3 ) , x ( 4 ) = 0$$

question 14

Multiple Choice

Solve the initial value problem for x as a function of t.
- $$\left( t ^ { 2 } - 5 t + 6 \right) \frac { d x } { d t } = 1 \quad ( t > 3 ) , x ( 4 ) = 0$$

• A) \(x = - \ln | t - 2 | + \ln | t - 3 | + \ln 2\)
• B) \(x = - \ln | t - 2 | + \ln | t - 3 | + 2\)
• C) \(x = - \ln | t - 2 | + \frac { 1 } { t - 3 } + \ln 2\)
• D) \(x = \ln | t - 2 | - \ln | t - 3 | + \ln 2\)

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