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Solve the Initial Value Problem for X as a Function (t2+2t)dxdt=2x+8,x(1)=1\left( t ^ { 2 } + 2 t \right) \frac { d x } { d t } = 2 x + 8 , x ( 1 ) = 1

question 413

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Solve the initial value problem for x as a function of t.
- (t2+2t) dxdt=2x+8,x(1) =1\left( t ^ { 2 } + 2 t \right) \frac { d x } { d t } = 2 x + 8 , x ( 1 ) = 1


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