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Solve the Problem y=3sin2xy = 3 \sin 2 x Is Given By

question 187

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Solve the problem.
-The length of one arch of the curve y=3sin2xy = 3 \sin 2 x is given by
L=0π/21+36cos22xdxL = \int _ { 0 } ^ { \pi / 2 } \sqrt { 1 + 36 \cos ^ { 2 } 2 x } d x
Estimate L\mathrm { L } by the Trapezoidal Rule with n=6\mathrm { n } = 6 .


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