Evaluate the Improper Integral or State That It Is Divergent$$\int _ { - \infty } ^ { \infty } \frac { 10 x } { \left( x ^ { 2 } - 1 \right) ^ { 2 } } d x$$

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The Answer of Evaluate the Improper Integral or State That It Is Divergent$$\int _ { - \infty } ^ { \infty } \frac { 10 x } { \left( x ^ { 2 } - 1 \right) ^ { 2 } } d x$$

Evaluate the Improper Integral or State That It Is Divergent $\int _ { - \infty } ^ { \infty } \frac { 10 x } { \left( x ^ { 2 } - 1 \right) ^ { 2 } } d x$

Definitions:

Evaluate the Improper Integral or State That It Is Divergent ∫−∞∞10x(x2−1)2dx\int _ { - \infty } ^ { \infty } \frac { 10 x } { \left( x ^ { 2 } - 1 \right) ^ { 2 } } d x∫−∞∞​(x2−1)210x​dx

Definitions:

Evaluate the Improper Integral or State That It Is Divergent $\int _ { - \infty } ^ { \infty } \frac { 10 x } { \left( x ^ { 2 } - 1 \right) ^ { 2 } } d x$