Provide an appropriate response.
-Here is an argument that ln2=∞−∞ . Where does the argument go wrong?
ln2=ln1+ln2=ln1−ln21
=limb→∞ln(bb−1)−ln21 =limb→∞[lnxx−1]2b
=limb→∞[ln(x−1)−lnx]2b
=limb→∞∫2b(x−11−x1)dx
=∫2∞(x−11−x1)dx
Here is an argument that ln2=∞−∞.
ln2=ln1+ln2=ln1−ln21
=limb→∞ln(bb−1)−ln21
=limb→∞[lnxx−1]2b
=limb→∞[ln(x−1)−lnx]2b
=limb→∞∫2b(x−11−x1)dx
=∫2∞(x−11−x1)dx
=∫2∞x−11dx−∫2∞x1dx
=limb→∞[ln(x−1)]bb−lim[lnx]
=∞−∞
=∫2∞x−11dx−∫2∞x1dx
=limb→∞[ln(x−1)]2b−limb→∞[lnx]2b
=∞−∞
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