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Provide an Appropriate Response 2e2xdx=12e4<0.0092\int _ { 2 } ^ { \infty } e ^ { - 2 x } \mathrm { dx } = \frac { 1 } { 2 } \mathrm { e } ^ { - 4 } < 0.0092

question 164

Essay

Provide an appropriate response.
-(a) Show that 2e2xdx=12e4<0.0092\int _ { 2 } ^ { \infty } e ^ { - 2 x } \mathrm { dx } = \frac { 1 } { 2 } \mathrm { e } ^ { - 4 } < 0.0092 and hence that 2ex2dx<0.0092\int _ { 2 } ^ { \infty } \mathrm { e } ^ { - \mathrm { x } ^ { 2 } } \mathrm { dx } < 0.0092 .
(b) Explain why this means that 0ex2dx\int _ { 0 } ^ { \infty } \mathrm { e } ^ { - \mathrm { x } ^ { 2 } } \mathrm { dx } can be replaced by 02ex2dx\int _ { 0 } ^ { 2 } \mathrm { e } ^ { - \mathrm { x } ^ { 2 } } \mathrm { dx } without introducing an error of magnitude greater than 0.0092.0.0092 .


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