Solve the Problem $y = \frac { 7 } { \sqrt { 6 x + 1 } } , x = 0 , x = 3$

question 95

Multiple Choice

Solve the problem.
-Find the volume of the solid that is generated by revolving the area bounded by $y = \frac { 7 } { \sqrt { 6 x + 1 } } , x = 0 , x = 3$ , and $y = 0$ about the $x$ -axis.

• A) \(\frac { 7 } { 6 } \pi \ln ( 6 )\)
• B) \(\frac { 49 } { 6 } \pi \ln ( 6 )\)
• C) \(\frac { 7 \sqrt { 6 } } { 6 } \pi \ln ( 19 )\)
• D) \(\frac { 49 } { 6 } \pi \ln ( 19 )\)

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