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A Variable Force of Magnitude F(x)F ( x ) Moves a Body of Mass

question 27

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A variable force of magnitude F(x) F ( x ) moves a body of mass mm along the xx -axis from x1x _ { 1 } to x2x _ { 2 } . The net work done by the force in moving the body from x1x _ { 1 } to x2x _ { 2 } is W=x1x2F(x) dx=12m2212mv12W = \int _ { x _ { 1 } } ^ { x _ { 2 } } F ( x ) d x = \frac { 1 } { 2 } m _ { 2 } { } ^ { 2 } - \frac { 1 } { 2 } m v _ { 1 } ^ { 2 } , where v1v _ { 1 } and v2v _ { 2 } are the body's velocities at x1x _ { 1 } and x2x _ { 2 } . Knowing that the work done by the force equals the change in the body's kinetic energy, solve the problem.
-A 2-oz tennis ball was served at 140ft/sec140 \mathrm { ft } / \mathrm { sec } about ( 95mph95 \mathrm { mph } ) . How much work was done on the ball to make it go this fast? (To find the ball's mass from its weight, express the weight in pounds and divide by 32ft/sec232 \mathrm { ft } / \mathrm { sec } ^ { 2 } , the acceleration of gravity.)


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