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Set Up an Integral for the Area of the Surface y=x3,0x2;x-axis y = x ^ { 3 } , 0 \leq x \leq 2 ; x \text {-axis }

question 69

Multiple Choice

Set up an integral for the area of the surface generated by revolving the given curve about the indicated axis.
- y=x3,0x2;x-axis y = x ^ { 3 } , 0 \leq x \leq 2 ; x \text {-axis }

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