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Solve the Problem 41 g(t)dt=4\int _ { - 4 } ^ { - 1 } \mathrm {~g} ( \mathrm { t } ) \mathrm { dt } = 4

question 189

Multiple Choice

Solve the problem.
-Suppose that 41 g(t) dt=4\int _ { - 4 } ^ { - 1 } \mathrm {~g} ( \mathrm { t } ) \mathrm { dt } = 4 . Find 41g(x) 4dx\int _ { - 4 } ^ { - 1 } \frac { \mathrm { g } ( \mathrm { x } ) } { 4 } \mathrm { dx } and 14g(t) dt\int _ { - 1 } ^ { - 4 } - \mathrm { g } ( \mathrm { t } ) \mathrm { dt } .


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