SHORT ANSWER$$\text { Use the } \max - \min \text { inequality to show that } 1 \leq \int _ { 0 } ^ { 1 } \sqrt { 1 + x ^ { 4 } } \mathrm { dx } \leq 2$$

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The Answer of SHORT ANSWER$$\text { Use the } \max - \min \text { inequality to show that } 1 \leq \int _ { 0 } ^ { 1 } \sqrt { 1 + x ^ { 4 } } \mathrm { dx } \leq 2$$

SHORT ANSWER $\text { Use the } \max - \min \text { inequality to show that } 1 \leq \int _ { 0 } ^ { 1 } \sqrt { 1 + x ^ { 4 } } \mathrm { dx } \leq 2$

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SHORT ANSWER Use the max⁡−min⁡ inequality to show that 1≤∫011+x4dx≤2\text { Use the } \max - \min \text { inequality to show that } 1 \leq \int _ { 0 } ^ { 1 } \sqrt { 1 + x ^ { 4 } } \mathrm { dx } \leq 2 Use the max−min inequality to show that 1≤∫01​1+x4​dx≤2

Definitions:

SHORT ANSWER $\text { Use the } \max - \min \text { inequality to show that } 1 \leq \int _ { 0 } ^ { 1 } \sqrt { 1 + x ^ { 4 } } \mathrm { dx } \leq 2$