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Evaluate the Integral Using the Given Substitution dx6x+3,u=6x+3\int \frac { d x } { \sqrt { 6 x + 3 } } , \quad u = 6 x + 3

question 82

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Evaluate the integral using the given substitution.
- dx6x+3,u=6x+3\int \frac { d x } { \sqrt { 6 x + 3 } } , \quad u = 6 x + 3

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