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Solve the Initial Value Problem A) r=16csc315θcot215θ+3\mathrm { r } = \frac { 1 } { 6 } \csc ^ { 3 } 15 \theta \cot ^ { 2 } 15 \theta + 3

question 261

Multiple Choice

Solve the initial value problem.
- drdθ=csc215θcot15θ,r(π4) =3\frac { \mathrm { dr } } { \mathrm { d } \theta } = \csc ^ { 2 } 15 \theta \cot 15 \theta , \quad \mathrm { r } \left( \frac { \pi } { 4 } \right) = 3


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