Find the Derivative at Each Critical Point and Determine the Local

question 336

Multiple Choice

Find the derivative at each critical point and determine the local extreme values.
- $y = \left\{ \begin{array} { l l } - \frac { 1 } { 4 } x ^ { 2 } - \frac { 1 } { 2 } x + \frac { 15 } { 4 } , & x \leq 1 \\x ^ { 3 } - 6 x ^ { 2 } + 8 x , & x > 1\end{array} \right.$

• A)
• \(\begin{array}{l|l|l|l}
• \text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\
• \hline x=-1 & 0 & \text { local min } & 4 \\
• x=3.15 & 0 & \text { local max } & -3.08
• \end{array}\)
• B)
• \(\begin{array}{l|l|l|l}
• \text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\
• \hline x=-1 & \text { undefined } & \text { local min } & 4 \\
• x=3.15 & 0 & \text { local max } & -3.08
• \end{array}\)
• C)
• \(\begin{array}{l|l|l|l}
• \text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\
• \hline x=-1 & 0 & \text { local max } & 4 \\
• x=3.15 & 0 & \text { local min } & -3.08
• \end{array}\)
• D)
• \(\begin{array}{l|l|l|l}
• \text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\
• \hline x=1 & 0 & \text { local max } & 4 \\
• x=3.15 & \text { undefined } & \text { local max } & -3.08
• \end{array}\)

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