Find a Value of C That Makes the Function Continuous $f ( x ) = \left\{ \begin{array} { c c } \frac { x + 3 } { 5 | x + 3 | ^ { \prime } } & x \neq - 3 \\c , & x = - 3\end{array} ; x = - 3 \right.$

question 362

Multiple Choice

Find a value of c that makes the function continuous at the given value of x. If it is impossible, state this.
- $f ( x ) = \left\{ \begin{array} { c c } \frac { x + 3 } { 5 | x + 3 | ^ { \prime } } & x \neq - 3 \\c , & x = - 3\end{array} ; x = - 3 \right.$

• A) 5
• B) Impossible
• C) -3
• D) 3

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