Solve the Problem$h 0$ , Applying Newton's Method To$$f ( x ) = \left\{ \begin{array} { l l } \sqrt { x - 8 } , & x \geq 8 \ - \sqrt { 8 - x } , & x

Question

Solve the Problem$h > 0$ , Applying Newton's Method To$$f ( x ) = \left\{ \begin{array} { l l } 
\sqrt { x - 8 } , & x \geq 8 \
- \sqrt { 8 - x } , & x < 8
\end{array} \right.$$

Examlex · Accepted Answer

The Answer of Solve the Problem$h > 0$ , Applying Newton's Method To$$f ( x ) = \left\{ \begin{array} { l l } 
\sqrt { x - 8 } , & x \geq 8 \
- \sqrt { 8 - x } , & x < 8
\end{array} \right.$$

Solve the Problem $h > 0$ , Applying Newton's Method To $f ( x ) = \left\{ \begin{array} { l l } \sqrt { x - 8 } , & x \geq 8 \\- \sqrt { 8 - x } , & x < 8\end{array} \right.$

Definitions:

Solve the Problem h>0h > 0h>0 , Applying Newton's Method To f(x)={x−8,x≥8−8−x,x<8f ( x ) = \left\{ \begin{array} { l l } \sqrt { x - 8 } , & x \geq 8 \\- \sqrt { 8 - x } , & x < 8\end{array} \right.f(x)={x−8​,−8−x​,​x≥8x<8​

Definitions:

Solve the Problem $h > 0$ , Applying Newton's Method To $f ( x ) = \left\{ \begin{array} { l l } \sqrt { x - 8 } , & x \geq 8 \\- \sqrt { 8 - x } , & x < 8\end{array} \right.$