Solve the Initial Value Problem $$\frac { d y } { d x } = \frac { 1 } { x ^ { 3 } } + x , x > 0 ; y ( 1 ) = 2$$

question 259

Multiple Choice

Solve the initial value problem.
- $$\frac { d y } { d x } = \frac { 1 } { x ^ { 3 } } + x , x > 0 ; y ( 1 ) = 2$$

• A) \(y = \frac { 4 } { x ^ { 4 } } + \frac { x ^ { 2 } } { 2 } - \frac { 5 } { 2 }\)
• B) \(y = \frac { - 1 } { 2 x ^ { 2 } } + \frac { x ^ { 2 } } { 2 }\)
• C) \(y = - \frac { 1 } { 2 x ^ { 2 } } + \frac { x ^ { 2 } } { 2 } + 2\)
• D) \(y = - \frac { 1 } { 2 x ^ { 2 } } + \frac { 5 } { 2 }\)

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