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Solve the Problem g=9.8 m/sec2g = 9.8 \mathrm {~m} / \mathrm { sec } ^ { 2 }

question 200

Multiple Choice

Solve the problem.
-At about what velocity do you enter the water is you jump from a 15 meter cliff? (Use g=9.8 m/sec2g = 9.8 \mathrm {~m} / \mathrm { sec } ^ { 2 } .)


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