Find the Derivative $$y = \frac { \sin x } { 9 x } + \frac { 9 x } { \sin x }$$

question 8

Multiple Choice

Find the derivative.
- $$y = \frac { \sin x } { 9 x } + \frac { 9 x } { \sin x }$$

• A) \(\frac { d y } { d x } = \frac { \sin x - x \cos x } { 81 x ^ { 2 } } + \frac { 9 x \cos x - 9 \sin x } { \sin ^ { 2 } x }\)
• B) \(\frac { d y } { d x } = \frac { x \cos x + \sin x } { 9 x ^ { 2 } } + \frac { 9 \sin x + 9 x \cos x } { \sin ^ { 2 } x }\)
• C) \(\frac { d y } { d x } = \frac { \cos x } { 9 } + \frac { 9 } { \cos x }\)
• D) \(\frac { d y } { d x } = \frac { x \cos x - \sin x } { 9 x ^ { 2 } } + \frac { 9 \sin x - 9 x \cos x } { \sin ^ { 2 } x }\)

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