Solve the Problem $$\mathrm { L } = \frac { 1 } { \sqrt { 2 } \pi \mathrm { t } ^ { 2 } \mathrm { n } }$$

question 65

Multiple Choice

Solve the problem.
-Under standard conditions, molecules of a gas collide billions of times per second. If each molecule has diametes average distance between collisions is given by
$$\mathrm { L } = \frac { 1 } { \sqrt { 2 } \pi \mathrm { t } ^ { 2 } \mathrm { n } }$$
where $n$ , the volume density of the gas, is a constant. Find $\frac { \mathrm { d } ^ { 2 } \mathrm {~L} } { \mathrm { dt } ^ { 2 } }$ .

• A) \(\frac { \mathrm { d } ^ { 2 } \mathrm {~L} } { \mathrm { dt } ^ { 2 } } = - \frac { 2 } { \sqrt { 2 } \pi \mathrm { t } ^ { 3 } \mathrm { n } }\)
• B) \(\frac { d ^ { 2 } L } { d t ^ { 2 } } = - \frac { 2 } { \sqrt { 2 } \pi t ^ { 2 } n }\)
• C) \(\frac { d ^ { 2 } L } { d t ^ { 2 } } = - \frac { 6 } { \sqrt { 2 } \pi t ^ { 4 } n }\)
• D) \(\frac { \mathrm { d } ^ { 2 } \mathrm {~L} } { d \mathrm { t } ^ { 2 } } = \frac { 6 } { \sqrt { 2 } \pi \mathrm { t } ^ { 4 } \mathrm { n } }\) t, the

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