Find the Derivative $$p = \frac { \sec q + \csc q } { \csc q }$$

question 158

Multiple Choice

Find the derivative.
- $$p = \frac { \sec q + \csc q } { \csc q }$$

• A) \(\frac { d p } { d q } = - \csc q \cot q\)
• B) \(\frac { \mathrm { dp } } { \mathrm { dq } } = \sec ^ { 2 } \mathrm { q }\)
• C) \(\frac { d p } { d q } = \sec q \tan q\)
• D) \(\frac { \mathrm { dp } } { \mathrm { dq } } = \sec ^ { 2 } \mathrm { q } + 1\)

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