Find the Derivative $$p = \frac { \sec q + \csc q } { \csc q }$$

question 158

Multiple Choice

Find the derivative.
- $$p = \frac { \sec q + \csc q } { \csc q }$$

• A) \(\frac { d p } { d q } = - \csc q \cot q\)
• B) \(\frac { \mathrm { dp } } { \mathrm { dq } } = \sec ^ { 2 } \mathrm { q }\)
• C) \(\frac { d p } { d q } = \sec q \tan q\)
• D) \(\frac { \mathrm { dp } } { \mathrm { dq } } = \sec ^ { 2 } \mathrm { q } + 1\)

---

Definitions:

Behavior Therapy

A type of psychotherapy that focuses on changing undesirable behaviors through conditioning techniques and environmental changes.

Psychotherapy

A general term for treating mental health problems by talking with a psychologist, psychiatrist, or other mental health provider.

Transference

In psychotherapy, the process by which patients project feelings and attitudes from past relationships onto the therapist.

Freud

Sigmund Freud, an Austrian neurologist and the founder of psychoanalysis, known for his theories about the unconscious mind and mechanisms of repression.