Solve the Problem $\mathrm { PV } = \mathrm { c }$

question 62

Multiple Choice

Solve the problem. Round your answer, if appropriate.
-Boyle's law states that if the temperature of a gas remains constant, then $\mathrm { PV } = \mathrm { c }$ , where $\mathrm { P } =$ pressure, $V =$ volume, and $c$ is a constant. Given a quantity of gas at constant temperature, if $V$ is decreasing at a rate of 9 in. $3 / \mathrm { sec }$ , at what rate is $\mathrm { P }$ increasing when $\mathrm { P } = 90 \mathrm { lb } / \mathrm { in } ^ { 2 }$ and $\mathrm { V } = 70 \mathrm { in } .3$ ? (Do not round your answer.)

• A) \(700 \mathrm { lb } /\) in. \(^ { 2 }\) per sec
• B) \(\frac { 81 } { 7 } \mathrm { lb } /\) in. \(^ { 2 }\) per sec
• C) \(\frac { 81 } { 49 } \mathrm { lb } / \mathrm { in } ^ { 2 }\) per sec
• D) \(7 \mathrm { lb } /\) in. \(^ { 2 }\) per sec

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