$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$

question 222

Multiple Choice

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
- $$\lim _ { x \rightarrow 0 } \frac { \sin x \cos 4 x } { x + x \cos 5 x }$$

• A) \(\frac { 1 } { 2 }\)
• B) does not exist
• C) \(\frac { 4 } { 5 }\)
• D) 0

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