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Use the Given Transformation to Evaluate the Integral Where RR Is the Interior of the Ellipsoid

question 243

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Use the given transformation to evaluate the integral.
- x=6u,y=9v,z=2w;(x236+y281+z24) 3dxdy\begin{array} { l } x = 6 u , y = 9 \mathrm { v } , z = 2 w ; \\\quad \iiint \left( \frac { x ^ { 2 } } { 36 } + \frac { y ^ { 2 } } { 81 } + \frac { z ^ { 2 } } { 4 } \right) ^ { 3 } d x d y\end{array}
where RR is the interior of the ellipsoid x236+y281+z24=1\frac { x ^ { 2 } } { 36 } + \frac { y ^ { 2 } } { 81 } + \frac { z ^ { 2 } } { 4 } = 1

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