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Use the Given Transformation to Evaluate the Integral Where RR Is the Interior of the Ellipsoid

question 145

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Use the given transformation to evaluate the integral.
- x=4u,y=5v,z=7w;(x216+y225+z249) πdxdy\begin{array} { l } x = 4 u , y = 5 v , z = 7 w ; \\\quad \iiint \left( \frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 25 } + \frac { z ^ { 2 } } { 49 } \right) ^ { \pi } d x d y\end{array}
where RR is the interior of the ellipsoid x216+y225+z249=1\frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 25 } + \frac { z ^ { 2 } } { 49 } = 1

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