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Find Two Paths of Approach from Which One Can Conclude sin(1y)1\left| \sin \left( \frac { 1 } { y } \right) \right| \leq 1

question 35

Essay

Find two paths of approach from which one can conclude that the function has no limit as (x, y) approaches (0, 0).
-Does knowing that sin(1y)1\left| \sin \left( \frac { 1 } { y } \right) \right| \leq 1 tell you anything about lim(x,y)(0,0)sin(x)sin(1y)\lim _ { ( x , y ) \rightarrow ( 0,0 ) } \sin ( x ) \sin \left( \frac { 1 } { y } \right) ? Give reasons for your answer.


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