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Find the Torsion of the Space Curve A) τ=625\tau = - \frac { 6 } { 25 }

question 121

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Find the torsion of the space curve.
- r(t) =(2+10sin25t) i+3tj+(2+10cos25t) k\mathbf { r } ( \mathrm { t } ) = \left( 2 + 10 \sin \frac { 2 } { 5 } \mathrm { t } \right) \mathbf { i } + 3 \mathrm { tj } + \left( 2 + 10 \cos \frac { 2 } { 5 } \mathrm { t } \right) \mathbf { k }


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