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Solve the Problem 250 km250 \mathrm {~km} Above the Earth's Surface a=\mathrm { a } =

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Solve the problem.
-A space shuttle is in a circular orbit 250 km250 \mathrm {~km} above the Earth's surface. Use Kepler's third law (with a=\mathrm { a } = Earth's radius +250 km) + 250 \mathrm {~km} ) to find the orbital period of the satellite. (G=6.67×1011Nm2 kg2\left( \mathrm { G } = 6.67 \times 10 ^ { - 11 } \mathrm { Nm } ^ { 2 } \mathrm {~kg} ^ { - 2 } \right. , M=5.97×1024 kg\mathrm { M } = 5.97 \times 10 ^ { 24 } \mathrm {~kg} and Earth's radius is 6.37×106 m6.37 \times 10 ^ { 6 } \mathrm {~m} ) .


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