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Find the Length of the Curve x=12t2,y=19(6t+9)3/2,0t1x = \frac { 1 } { 2 } t ^ { 2 } , y = \frac { 1 } { 9 } ( 6 t + 9 ) ^ { 3 / 2 } , 0 \leq t \leq 1

question 85

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Find the length of the curve.
- x=12t2,y=19(6t+9) 3/2,0t1x = \frac { 1 } { 2 } t ^ { 2 } , y = \frac { 1 } { 9 } ( 6 t + 9 ) ^ { 3 / 2 } , 0 \leq t \leq 1


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