Use the Limit Comparison Test to Determine If the Series$$\sum _ { n = 1 } ^ { \infty } \frac { ( \ln n ) ^ { 2 } } { \sqrt { n } ( 4 n - 5 \sqrt { n } ) }$$

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The Answer of Use the Limit Comparison Test to Determine If the Series$$\sum _ { n = 1 } ^ { \infty } \frac { ( \ln n ) ^ { 2 } } { \sqrt { n } ( 4 n - 5 \sqrt { n } ) }$$

Use the Limit Comparison Test to Determine If the Series $\sum _ { n = 1 } ^ { \infty } \frac { ( \ln n ) ^ { 2 } } { \sqrt { n } ( 4 n - 5 \sqrt { n } ) }$

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Use the Limit Comparison Test to Determine If the Series ∑n=1∞(ln⁡n)2n(4n−5n)\sum _ { n = 1 } ^ { \infty } \frac { ( \ln n ) ^ { 2 } } { \sqrt { n } ( 4 n - 5 \sqrt { n } ) }n=1∑∞​n​(4n−5n​)(lnn)2​

Definitions:

Use the Limit Comparison Test to Determine If the Series $\sum _ { n = 1 } ^ { \infty } \frac { ( \ln n ) ^ { 2 } } { \sqrt { n } ( 4 n - 5 \sqrt { n } ) }$