Find the Series' Radius of Convergence$$\sum _ { n = 0 } ^ { \infty } \frac { n ( n + 1 ) ( n + 2 ) } { 8 ^ { n } } ( x - \pi ) ^ { n }$$

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The Answer of Find the Series' Radius of Convergence$$\sum _ { n = 0 } ^ { \infty } \frac { n ( n + 1 ) ( n + 2 ) } { 8 ^ { n } } ( x - \pi ) ^ { n }$$

Find the Series' Radius of Convergence $\sum _ { n = 0 } ^ { \infty } \frac { n ( n + 1 ) ( n + 2 ) } { 8 ^ { n } } ( x - \pi ) ^ { n }$

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Find the Series' Radius of Convergence ∑n=0∞n(n+1)(n+2)8n(x−π)n\sum _ { n = 0 } ^ { \infty } \frac { n ( n + 1 ) ( n + 2 ) } { 8 ^ { n } } ( x - \pi ) ^ { n }n=0∑∞​8nn(n+1)(n+2)​(x−π)n

Definitions:

Find the Series' Radius of Convergence $\sum _ { n = 0 } ^ { \infty } \frac { n ( n + 1 ) ( n + 2 ) } { 8 ^ { n } } ( x - \pi ) ^ { n }$