For What Values of X Does the Series Converge Conditionally$$\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } ( x + 6 ) ^ { n } } { n 5 ^ { n } }$$

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The Answer of For What Values of X Does the Series Converge Conditionally$$\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } ( x + 6 ) ^ { n } } { n 5 ^ { n } }$$

For What Values of X Does the Series Converge Conditionally $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } ( x + 6 ) ^ { n } } { n 5 ^ { n } }$

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For What Values of X Does the Series Converge Conditionally ∑n=1∞(−1)n+1(x+6)nn5n\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } ( x + 6 ) ^ { n } } { n 5 ^ { n } }n=1∑∞​n5n(−1)n+1(x+6)n​

Definitions:

For What Values of X Does the Series Converge Conditionally $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } ( x + 6 ) ^ { n } } { n 5 ^ { n } }$