Find the Sum of the Series as a Function of X

question 364

Multiple Choice

Find the sum of the series as a function of x.
- $\sum _ { n = 0 } ^ { \infty } \frac { ( x - 1 ) ^ { 2 n } } { 6 ^ { n } }$

• A) \(- \frac { 6 } { ( x - 1 ) ^ { 2 } - 6 }\)
• B)\( - \frac { 6 } { ( x - 1 ) ^ { 2 } + 6 }\)
• C) \(\frac { 6 } { ( x - 1 ) ^ { 2 } + 6 }\)
• D) \(\frac { 6 } { ( x - 1 ) ^ { 2 } - 6 }\)

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