Use Substitution to Find the Taylor Series at X = $$\ln \left( \frac { 1 + x ^ { 3 } } { 1 - x ^ { 3 } } \right)$$

question 314

Multiple Choice

Use substitution to find the Taylor series at x = 0 of the given function.
- $$\ln \left( \frac { 1 + x ^ { 3 } } { 1 - x ^ { 3 } } \right)$$

• A) \(\sum _ { n = 0 } ^ { \infty } \frac { x ^ { 6 n + 3 } } { 6 n + 3 }\)
• B) \(\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } x ^ { 3 n } } { n }\)
• C) \(2 \sum _ { n = 0 } ^ { \infty } \frac { x ^ { 6 n + 3 } } { 2 n + 1 }\)
• D) \(2 \sum _ { n = 0 } ^ { \infty } \frac { x ^ { 6 n + 3 } } { 6 n + 3 }\)

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